Question

25%*y +50% -y-3/4*y+4*y=10

Answer 1

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Answer 2

\(25\%y+50\%-y-\frac{3}{4}\cdot y+4\cdot y=10\)

\(\frac{1}{4}y+\frac{1}{2}-y-\frac{1}{4}y+4y=10\)

\(y\left(\frac{1}{4}-\frac{1}{4}-1+4\right)=10-\frac{1}{2}\)

\(3y=\frac{19}{2}\)

\(y=\frac{19}{2}:3\)

\(y=\frac{19}{6}\)

Answer 3

\(25\%\times y+50\%-y-\frac{3}{4}\times y+4\times y=10\)

\(\frac{1}{4}\times y+\frac{1}{2}-y-\frac{3}{4}\times y+4\times y=10\)

\(\frac{1}{4}\times y-y-\frac{3}{4}\times y+4\times y=10-\frac{1}{2}\)

\(y\times\left(\frac{1}{4}-1-\frac{3}{4}+4\right)=\frac{19}{2}\)

\(y\times\frac{5}{2}=\frac{19}{2}\)

\(y=\frac{19}{2}:\frac{5}{2}\)

\(y=\frac{19}{5}\)