\(25\%+\frac{1}{2}\left(x-\frac{4}{5}\right)=2,6\)
\(\frac{1}{4}+\frac{1}{2}\left(x-\frac{4}{5}\right)=2,6\)
\(\frac{1}{4}+\frac{1}{2}x-\frac{1}{2}\cdot\frac{4}{5}=2,6\)
\(\frac{1}{2}x-\frac{2}{5}=2,6-\frac{1}{4}\)
\(\frac{1}{2}x=2,35+\frac{2}{5}\)
\(\frac{1}{2}x=2,75\)
\(x=2,75:\frac{1}{2}=5,5\)
\(25\%+\frac{1}{2}\left(x-\frac{4}{5}\right)=2,6\)
\(\frac{1}{4}+\frac{1}{2}\left(x-\frac{4}{5}\right)=2,6\)
\(\frac{1}{4}+\frac{1}{2}x-\frac{1}{2}.\frac{4}{5}=2,6\)
\(\frac{1}{2}x-\frac{2}{5}=2,6-\frac{1}{4}\)
\(\frac{1}{2}x=2,35+\frac{2}{5}\)
\(\frac{1}{2}x=2,75\)
\(x=2,75:\frac{1}{2}=5,5\)
xin lỗi để mình sửa lại
\(25\%x+\frac{1}{2}\left(x-\frac{4}{5}\right)=2,6\)
\(\frac{1}{4}x+\frac{1}{2}x-\frac{2}{5}=\frac{13}{5}\)
\(\left(\frac{1}{4}+\frac{1}{2}\right)x=\frac{13}{5}+\frac{2}{5}=\frac{15}{5}=3\)
\(\frac{3}{4}x=3\)
\(x=3:\frac{3}{4}=\frac{12}{3}=4\)