\(\dfrac{242}{363}+\dfrac{1616}{2121}=\dfrac{2}{7}y\)
\(\dfrac{2\cdot121}{3\cdot121}+\dfrac{16\cdot101}{21\cdot101}=\dfrac{2}{7}y\)
\(\dfrac{2}{7}y=\dfrac{2}{3}+\dfrac{16}{21}\)
\(\dfrac{2}{7}y=\dfrac{10}{7}\)
\(y=\dfrac{10}{7}\div\dfrac{2}{7}=5\)