\(\frac{2}{3}\times x+\frac{1}{2}=\frac{1}{10}\)
\(\Rightarrow\frac{2}{3}\times x=\frac{1}{10}-\frac{1}{2}\)
\(\Rightarrow\frac{2}{3}\times x=-\frac{2}{5}\)
\(\Rightarrow x=-\frac{2}{5}:\frac{2}{3}\)
\(\Rightarrow x=-\frac{2}{5}.\frac{3}{2}\)
\(\Rightarrow x=-\frac{3}{5}\)
\(\frac{2}{3}\) . x + \(\frac{1}{2}\) = \(\frac{1}{10}\)
=> \(\frac{2}{3}\) . x = \(\frac{1}{10}\) - \(\frac{1}{2}\) = \(\frac{-2}{5}\)
=> x= \(\frac{-2}{5}\) : \(\frac{2}{3}\) = \(\frac{-3}{5}\) Vậy x = \(\frac{-3}{5}\)