Các câu hỏi tương tự
Tìm x :
a. 10 x X - 1 - 3 - 5 - 7 - .... - 19 = 2 + 4 + 6 + .... + 20 .
b. 3x / 2 + 3x / 6 + 3x / 12 + 3x / 20 + 3x / 30 = 10
1) 5.(x-2)+27=4x-8
2) 3.(x+1)+2.(x+2)=-13
3)(2x+4).(5-x)=0
4)x2 -3x=0
5) x2 -3x+2=0
2/3x(x-5)=5/3
BÀI 2: tìm số hữu tỹ X , biết rằnga,frac{-3}{2}-2X+frac{3}{4}-22b, (frac{-2}{3}x-frac{3}{5})(frac{3}{-2}-frac{10}{3})frac{2}{5}c,frac{x}{2}-left(frac{3x}{5}-frac{13}{5}right)-left(frac{7}{5}+frac{7}{10}.xright)d,frac{2x-3}{3}+frac{-3}{2}frac{5-3x}{6}-frac{1}{3}e,frac{2}{3x}-frac{3}{12}frac{4}{5}-left(frac{7}{x}-2right)
Đọc tiếp
BÀI 2: tìm số hữu tỹ X , biết rằng
a,\(\frac{-3}{2}-2X+\frac{3}{4}=-2\)2
b, (\(\frac{-2}{3}x-\frac{3}{5}\))(\(\frac{3}{-2}-\frac{10}{3}\))=\(\frac{2}{5}\)
c,\(\frac{x}{2}-\left(\frac{3x}{5}-\frac{13}{5}\right)=-\left(\frac{7}{5}+\frac{7}{10}.x\right)\)
d,\(\frac{2x-3}{3}+\frac{-3}{2}=\frac{5-3x}{6}-\frac{1}{3}\)
e,\(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}-2\right)\)
5 9/10 : 3/2-[ 2 1/3x 4 1/2-2x 2 1/3 ] :7/4
3x/2-1/3=2/5+x
3x/2-1/3=2/5-x
a, 4x5^2-3x(24-9)=?
b, 7+6x(-1/2)^2=?
c,2•3•4•5•0=?
d, 1+2-2+3-3+4-4+5-5=?
tìm x biết 3x/2 - 1/3=2/5 + x