\(\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right).\left(-\dfrac{3}{2}-\dfrac{10}{3}\right)=\dfrac{2}{5}\)
\(\Leftrightarrow\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right).\left(-4\right)=\dfrac{2}{5}\)
\(\Leftrightarrow\left(-\dfrac{2}{3}x-\dfrac{3}{5}\right)=-\dfrac{1}{10}\)
\(\Leftrightarrow-\left(\dfrac{2}{3}x+\dfrac{3}{5}\right)=\dfrac{1}{10}\)
\(\Leftrightarrow\dfrac{2}{3}x+\dfrac{3}{5}=\dfrac{1}{10}\)
\(\Leftrightarrow\dfrac{2}{3}x=-\dfrac{1}{2}\)
\(\Leftrightarrow x=-\dfrac{3}{4}\)
Vậy x=\(\dfrac{-3}{4}\)
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