Question

22/9-(x+1/2)\(^2\)) =7/3       giúp em với càng nhanh càng tốt ạ! E cảm ơn nhiều !!

Answer 1

\(\frac{22}{9}-\left(x+\frac{1}{2}\right)^2=\frac{7}{3}\)

\(\left(x+\frac{1}{2}\right)^2=\frac{22}{9}-\frac{7}{3}\)

\(\left(x+\frac{1}{2}\right)^2=\frac{1}{9}\)

\(\left(x+\frac{1}{2}\right)^2=\left(\frac{1}{3}\right)^2\)

\(\Rightarrow x+\frac{1}{2}=\frac{1}{3}\)

\(x=\frac{1}{3}-\frac{1}{2}\)

\(x=-\frac{1}{6}\)

Answer 2

\(\frac{22}{9}-\left(x+\frac{1}{2}\right)^2=\frac{7}{3}\)

\(\left(x+\frac{1}{2}\right)^2=\frac{22}{9}=\frac{7}{3}\)\

\(\left(x+\frac{1}{2}\right)^2=\frac{22}{9}-\frac{21}{9}\)

\(\left(x+\frac{1}{2}\right)^2=\frac{1}{9}\)

\(\Rightarrow x+\frac{1}{2}=\pm\frac{1}{3}\)

TH1:\(x+\frac{1}{2}=\frac{1}{3}\)

       \(x=\frac{1}{3}-\frac{1}{2}\)

        \(x=-\frac{1}{6}\)

TH2:\(x+\frac{1}{2}=-\frac{1}{3}\)

        \(x=-\frac{1}{3}-\frac{1}{2}\)

       \(x=-\frac{5}{6}\)

Vậy \(x\in\left\{-\frac{1}{6};-\frac{5}{6}\right\}\)

Answer 3

x  +(22/9 -1/2) =7/3

x   +(44/18-9/18)=7/3 + 35/18

x                         =42/18+35/18

x                          =77/18

k nha bạn