a) \(2^2.3^{3x}-27^x=9^5\)
\(4.3^{3x}-\left(3^3\right)^x=\left(3^2\right)^5\)
\(4.3^{3x}-3^{3x}=3^{10}\)
\(3^{3x}\left(4-1\right)=3^{10}\)
\(3^{3x}.3=3^{10}\)
\(3^{3x+1}=3^{10}\)
3x + 1 = 10
3x = 9
x = 3.
b. \(5.3^x=135\)
\(3^x=27\)
\(3^x=3^3\)
x = 3.
c. \(5^x.5^4=5^{20}\)
\(5^{x+4}=5^{20}\)
x + 4 = 20
x = 16