Question

2/1×3 + 2/3×5 + 2/5×7+...+ 2/99×101

Answer 1

\(\frac{2}{1}\)\(\times\)3+\(\frac{2}{3}\)\(\times\)5+\(\frac{2}{5}\)\(\times\)7+...+\(\frac{2}{99}\)\(\times\)101

=(1-\(\frac{1}{3}\))+(\(\frac{1}{3}\)-\(\frac{1}{5}\))+(\(\frac{1}{5}\)-\(\frac{1}{7}\))+...+(\(\frac{1}{99}\)-\(\frac{1}{100}\))

=1-\(\frac{1}{100}\)

=\(\frac{100}{101}\)

Answer 2

TÍCH CHO MK NHA 

CHÚC BẠN HỌC TỐT !

Answer 3

Thanks bạn