VT=[(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)]/2
=[(2^2-1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)]/2
=[(2^4-1(2^4+1)(2^8+1)(2^16+1)]/2
=[(2^8-1)(2^8+1)(2^16+1)]/2
=[(2^16-1)(2^16+1)]/2
=(2^32-1)/2
(2+1)(2^2+1)(2^4 +1)(2^8+1)(2^16+1) - 2^32 = ?
So sánh A và B biết: A=(2+1)×(2^2+1)×(2^4+1)×(2^8+1)×(2^16+1)×(2^16+1) và B=2^32
rút gọnA=(2+1)*(2^2+1)(2^4+1)*(2^8+1)*(2^16+1)*(2^32+1)
bài 6:tính nhanh
7)1\(^2\)-2\(^2\)+3\(^2\)-4\(^2\)+....-2004\(^2\)+2005\(^2\)
8) (2+1)(2\(^2\)+1)(2\(^4\)+1)(2\(^8\)+1)(2\(^{16}\)+1)(2\(^{32}\)+1)-2\(^{64}\)
tính: A=(2+1).(2^2+1).(2^4+1).(2^8+1).(2^16+1)+(2^32+1)-(2^64).
so sánh M = 2^32 và N = (2 + 1)(2^2 + 1)(2^4 + 1)(2^8 + 1)(2^16 + 1)
tính nhanh
3(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)
SO SÁNH A = 3(2^2+1)(2^4+1)(2^8+1)(2^16+1)+1 VÀ B =2^32
So Sánh
A=(2+1).(2^2+1).(2^4+1).(2^8+1).(2^16+1) và B=2^32
