\(\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^8.2.78}{2^8.104}=\frac{2}{13}\)
\(2^{10}.13+2^{10}.65\)/\(2^8.104\)
=\(\frac{2^{10}.\left(13+65\right)}{2^8.104}=\frac{2^{10}.78}{26624}=\frac{79872}{26624}=3\)
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