Cách 1 :
2010 - 2000/486 - 2(7^2 x 6)
= 5/51
Cách 2 :
2010 - 2000/486 - 2 ( 7^2 x 6 )
= 2029 , 607 843 137 25
k cho mk nha
Cách 1 :
2010 - 2000/486 - 2(7^2 x 6)
= 5/51
Cách 2 :
2010 - 2000/486 - 2 ( 7^2 x 6 )
= 2029 , 607 843 137 25
k cho mk nha
\(2010-2000:\orbr{\begin{cases}\\\end{cases}486}-2\left(49-6\right)\)
\(\orbr{\begin{cases}\\\end{cases}}6+\left(\frac{1}{2}\right)^3-\left|-\frac{1}{2}\right|\orbr{\begin{cases}\\\end{cases}\frac{3}{2}}\)
\(\orbr{\begin{cases}\\\end{cases}\left(-25\right)}.\left(-27\right).\left(-x\right)\orbr{\begin{cases}\\\end{cases}}:y\)với a = 5 ; b = -3
a) A=(7-9)\(^3\)+(-5)\(^7\):(-5)\(^5\)+2010\(^0\)
b)B=\(\orbr{\begin{cases}\\\end{cases}2.\left(-2\right)^2}\)+1):(-3)\(^2\)+9.7-(-2)\(^6\)
\(\orbr{\begin{cases}\\\end{cases}212}+\left(48-2xx_{ }^2^{ }\right):40-3=3\)
Tìm x , y nếu
\(a\orbr{\begin{cases}x+y=60\\\frac{x}{y}=\frac{3}{2}\end{cases}}\) b \(\orbr{\orbr{\begin{cases}\frac{x^2}{9}=\frac{y^2}{16}\\x^2+y^2=100\end{cases}}}\)
Giúp mình đi , làm ơn đấy , mình cần gấp , mk sẽ tick cho , cảm ơn các bn
\(\left(0,125+40\%-\frac{3}{40}\right)\):\(\orbr{\begin{cases}\\\end{cases}11\frac{3}{7}+8\frac{1}{2}-\left(\frac{13}{12}-5\frac{4}{7}\right)}\)
\(\orbr{\begin{cases}\\4\frac{1}{2}:2,5-40\%+\left(-\frac{1}{5}\right)\end{cases}}.\frac{5}{9}\)
0.2x \(\frac{15}{36}\)-\(\orbr{\begin{cases}2\\5\end{cases}}+\frac{2}{3}\)