Các câu hỏi tương tự
a/ (x+3) . (X+2)=0
b/(x-7) .(x+2005) =0
c/ 5. (x-7)+ 3. (x + 2) = 7 . (x - 5) + 2 . |-4| . ( -3) . 5
d/|x - 1| + 5. (x- 2 ) = 5. x - 4.|-2|
(1 + 1 + 1 ) x ( 2 + 2 + 2 ) x ( 3 + 3 + 3 ) x ( 5 + 5 + 5 ) = ?
1 x 2 x 3 =5
2 x 3 x 4=10
3 x 4 x 5 =17
4 x 5 x 6 =26
5 x 6 x 7 =37
6 x 7 x 8 =?
nêu qui luật trên
nêu đáp án luôn nha!
7/2.x-3/4=5/6– -2/3
5/6-(20%.x-3/4)=x+1/2
1 x 1 =
2 x 2 =
3 x 3 =
4 x 4 =
5 x 5 =
Tìm X : 5 + X -3 + 5 x 4 = X x 2-3 + 16
a)5-3.x=2
b)5+2:x=3
Chúc các bạn làm đúng
phần a
1 x 2 - 2 x 3 x 4 - 2 + 5 x 1 + 6 - ( 2 x 2 x 0 ) + 5 x 5
b, MA-Bfrac{sqrt{x}+2}{sqrt{x}+3}-left(frac{5}{x+sqrt{x}-6}+frac{1}{sqrt{x}-2}right)frac{sqrt{x}+2}{sqrt{x}+3}-frac{5}{x+sqrt{x}-6}-frac{1}{sqrt{x}-2}frac{left(sqrt{x}+2right)left(sqrt{x}-2right)}{x+sqrt{x}-6}-frac{5}{x+sqrt{x}-6}-frac{1left(sqrt{x}+3right)}{x+sqrt{x}-6}frac{x-4-5-sqrt{x}-3}{left(sqrt{x}+3right)left(sqrt{x}-2right)}frac{x-sqrt{x}-12}{left(sqrt{x}+3right)left(sqrt{x}-2right)}frac{x-4sqrt{x}+3sqrt{x}-12}{left(sqrt{x}+3right)left(sqrt{x}-2right)}frac{left(sqrt{x}-4right)left(sqrt{x...
Đọc tiếp
b, \(M=A-B=\frac{\sqrt{x}+2}{\sqrt{x}+3}-\left(\frac{5}{x+\sqrt{x}-6}+\frac{1}{\sqrt{x}-2}\right)\)
\(=\frac{\sqrt{x}+2}{\sqrt{x}+3}-\frac{5}{x+\sqrt{x}-6}-\frac{1}{\sqrt{x}-2}\)
\(=\frac{\left(\sqrt{x}+2\right)\left(\sqrt{x}-2\right)}{x+\sqrt{x}-6}-\frac{5}{x+\sqrt{x}-6}-\frac{1\left(\sqrt{x}+3\right)}{x+\sqrt{x}-6}\)
\(=\frac{x-4-5-\sqrt{x}-3}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}=\frac{x-\sqrt{x}-12}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}=\frac{x-4\sqrt{x}+3\sqrt{x}-12}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}\)\(=\frac{\left(\sqrt{x}-4\right)\left(\sqrt{x}+3\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+3\right)}=\frac{\sqrt{x}-4}{\sqrt{x}-2}\)
tìm x va y biet
a) (x+3) x (y-2) = 2
b) (x+3) x (y-2) = 5