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a,\(2\frac{4}{5}-1\frac{4}{15}\)
=\(\frac{14}{5}-\frac{19}{15}\)
= \(\frac{23}{15}\)
b, \(4-\frac{5}{7}\)
= \(\frac{28}{7}-\frac{5}{7}\)
= \(\frac{23}{7}\)
c, \(5:\frac{2}{3}\cdot\frac{3}{4}\)
\(=\frac{15}{2}\cdot\frac{3}{4}\)
= \(\frac{45}{8}\)
d, \(3\frac{1}{2}+2\frac{1}{3}=\frac{35}{6}\)
\(2\frac{4}{5}-1\frac{4}{15}=\frac{14}{5}-\frac{19}{15}=\frac{42}{15}-\frac{19}{15}=\frac{23}{15}\)
\(4-\frac{5}{7}=\frac{28}{7}-\frac{5}{7}=\frac{23}{7}\)
\(5:\frac{2}{3}\times\frac{4}{3}=5\times\frac{3}{2}\times\frac{4}{3}=10\)
\(3\frac{1}{2}+2\frac{1}{3}=\frac{7}{2}+\frac{7}{3}=\frac{21}{6}+\frac{14}{6}=\frac{35}{6}\)
61/15
23/7
45/8
35/6