Các câu hỏi tương tự
Giúp tớ giải toán này nha:
A=\(\frac{1}{1.2}\)+\(\frac{1}{2.3}\)+\(\frac{1}{3.4}\)+\(\frac{1}{4.5}\)+...+\(\frac{1}{19.20}\)
Tính nhanh :
a)\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}...+\frac{1}{98.99}+\frac{1}{99.100}\)
b)\(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{41.43}\)
c)\(\frac{5}{11.16}+\frac{5}{16.21}+\frac{5}{21.26}+...+\frac{5}{61.66}\)
d)\(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+...+\frac{1}{90}+\frac{1}{110}\)
A.\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{49.50}\)
So sánh A với 1
B.\(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{99.100}\)
So sánh B với \(\frac{1}{2}\)
tính giá trị biểu thức
A =\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}\)
B = \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{n.\left(n+1\right)}\)(n\(\in\)Z, n\(\ne\)0; n\(\ne\)-1)
Bài 9: tính
a, A= 1+2+3+4+....+100
b,B=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+........+\frac{1}{99.100}\)
c, C=\(\frac{10}{56}+\frac{10}{140}+\frac{10}{200}+.......+\frac{1}{1400}\)
Tính
A=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}\)
B=\(\left(1+\frac{1}{2}\right).\left(1+\frac{1}{3}\right).\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{99}\right)\)
Tính nhanh ( làm giùm nka mik like cho hjhj)
\(A=\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{19.20}\)
\(B=\frac{1}{99.100}-\frac{1}{98.99}-\frac{1}{97.98}-...-\frac{1}{1.2}\)
\(B=\frac{8}{3}.\frac{2}{5}.\frac{3}{8}.10.\frac{19}{92}\)
\(C=\frac{-5}{7}.\frac{2}{7}+\frac{-5}{7}.\frac{9}{14}+1\frac{5}{7}\)
\(D=\frac{12}{19}.\frac{7}{15}.\frac{-13}{17}.\frac{19}{12}.\frac{17}{13}\)
\(E=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{49.50}\)
Bài 1 : tính tổng sauP frac{1}{1.2}+frac{1}{2.3}+frac{1}{3.4}+...+frac{1}{9.10}S frac{2}{3.5}+frac{2}{5.7}+frac{2}{7.9}+...+frac{2}{97.99}Q frac{1}{2.3}+frac{1}{3.4}+frac{1}{4.5}+...+frac{1}{19.20}Dấu . là dấu nhân nhéBài 2 Tính tích P ( 1+frac{1}{2}) X ( 1+frac{1}{3}) x ( 1+frac{1}{4}) x ... x ( 1+frac{1}{99})
Đọc tiếp
Bài 1 : tính tổng sau
P = \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{9.10}\)
S = \(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{97.99}\)
Q = \(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{19.20}\)
Dấu " . " là dấu nhân nhé
Bài 2 Tính tích P = ( \(1+\frac{1}{2}\)) X ( \(1+\frac{1}{3}\)) x ( \(1+\frac{1}{4}\)) x ... x ( \(1+\frac{1}{99}\))