\(\frac{-1}{x-2}=\frac{x-2}{-9}\)ĐKXĐ: \(x\ne2\)
\(\Rightarrow\left(x-2\right)\left(x-2\right)=-1\cdot\left(-9\right)\)
\(\Rightarrow\left(x-2\right)^2=9\)
\(\Rightarrow\orbr{\begin{cases}x-2=3\\x-2=-3\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}}\)( thỏa mãn ĐKXĐ)
vậy..........