1)tính
a) \(\dfrac{1}{2}\):\(\dfrac{1}{4}\)-\(\dfrac{1}{6}\)=
b) ( \(\dfrac{5}{2}\)+\(\dfrac{1}{3}\)) : (1-\(\dfrac{2}{3}\))
c) (\(\dfrac{1}{3}\)-\(\dfrac{1}{3}\)) x \(\dfrac{9}{2}\)-\(\dfrac{6}{7}\)=
2) Tính
a) \(1\dfrac{1}{3}\)+\(2\dfrac{1}{2}\)=
b)\(3\dfrac{2}{5}\)-\(1\dfrac{1}{10}\)=
c)\(3\dfrac{1}{2}\) x \(1\dfrac{1}{7}\)=
d) \(4\dfrac{1}{6}\):\(2\dfrac{1}{3}\)=
1)
\(a)\dfrac{1}{2}:\dfrac{1}{4}-\dfrac{1}{6}=\dfrac{1}{2}\times4-\dfrac{1}{6}=2-\dfrac{1}{6}=\dfrac{11}{6}.\)
\(b)\left(\dfrac{5}{2}+\dfrac{1}{3}\right):\left(1-\dfrac{2}{3}\right)=\dfrac{17}{6}:\dfrac{1}{3}=\dfrac{17}{2}.\)
\(c)\left(\dfrac{1}{3}-\dfrac{1}{3}\right)\times\dfrac{9}{2}-\dfrac{6}{7}=0\times\dfrac{9}{2}-\dfrac{6}{7}=\dfrac{-6}{7}.\)
2)
\(a.1\dfrac{1}{3}+2\dfrac{1}{2}=\dfrac{4}{3}+\dfrac{5}{2}=\dfrac{23}{6}.\\ b.3\dfrac{2}{5}-1\dfrac{1}{10}=\dfrac{17}{5}-\dfrac{11}{10}=\dfrac{23}{10}.\\ c.3\dfrac{1}{2}\times1\dfrac{1}{7}=\dfrac{7}{2}\times\dfrac{8}{7}=\dfrac{8}{2}=4.\)
\(d,4\dfrac{1}{6}:2\dfrac{1}{3}=\dfrac{25}{6}:\dfrac{7}{3}=\dfrac{25}{6}.\dfrac{3}{7}=\dfrac{25}{14}.\)
