Question

1.Tính:

a, (2-1)(2+1)(2\(^2\)+1)(2\(^4\)+1)(2\(^8\)+1)

b, 8 (3\(^2\)+1)(3\(^4\)+1)(3\(^8\)+1)(3\(^{16}\)+1)(3\(^{23}\)+1)- 3\(^{94}\)

2. So sánh

A=2009*2009

B=2008*2010

Answer 1

Bài 1:

a) \(\left(2-1\right)\left(2+1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\)

\(=\left(2^2-1\right)\left(2^2+1\right)\left(2^4+1\right)\left(2^8+1\right)\)

\(=\left(2^4-1\right)\left(2^4+1\right)\left(2^8+1\right)\)

\(=\left(2^8-1\right)\left(2^8+1\right)\)

\(=2^{16}-1\)

b) Sửa đề \(8\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)-3^{64}\)

\(=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)-3^{64}\)

\(=\left(3^4-1\right)\left(3^4+1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)-3^{64}\)

\(=\left(3^8-1\right)\left(3^8+1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)-3^{64}\)

\(=\left(3^{16}-1\right)\left(3^{16}+1\right)\left(3^{32}+1\right)-3^{64}\)

\(=\left(3^{32}-1\right)\left(3^{32}+1\right)-3^{64}\)

\(=3^{64}-1-3^{64}\)

\(=-1\)

Bài 2:

Ta có:

\(A=2009.2009\)

\(A=2009\left(2008+1\right)\)

\(A=2009.2008+2009\)

Ta lại có:

\(B=2008.2010\)

\(B=2008\left(2009+1\right)\)

\(B=2008.2009+2008\)

Vì 2008.2009 = 2009.2008

2009 > 2008

=> 2008.2009 + 2009 > 2009.2008 + 2008

=> A > B

Answer 2

1,a,(2-1)(2+1)(2²+1)(2⁴+1)(2⁸+1)

=(2²-1)(2²+1)(2⁴+1)(2⁸+1)

=(2⁴-1) (2⁴+1)(2⁸+1)

=(2⁸ -1)(2⁸+1)=2¹⁶-1

2,

A=2009.2009=2009²

B=2008.2010=(2009-1)(2009+1)=2009²-1

Do2009²>2009²-1\(\Rightarrow A>B\)

Answer 3

bạn ơi! câu 1b bạn ghi sai đề rồi!