Question

1,tìm x

a,\(\frac{3}{4}\) \(-\)\(|2x+1|\)\(=\frac{7}{8}\)

b,\(2\times|2x-3|=\frac{1}{2}\)

c,\(7,5-3.|5-2x|=-4,5\)

d,\(|x+\frac{4}{15}|-|-3,75|=-|-2,15|\)

Answer 1

a) \(\frac{3}{4}-\left|2x+1\right|=\frac{7}{8}\)

\(\left|2x+1\right|=\frac{3}{4}-\frac{7}{8}\)

\(\left|2x+1\right|=-\frac{1}{8}\)

\(\Rightarrow x\in\varnothing\)

b) \(2.\left|2x-3\right|=\frac{1}{2}\)

\(\left|2x-3\right|=\frac{1}{4}\)

TH1: 2x - 3 = 1/4

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TH2: 2x -3  = -1/4

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rùi bn tự lm típ nhé! câu c dựa vào phần a;b là lm đk

d)\(\left|x+\frac{4}{15}\right|-\left|-3,75\right|=-\left|-2,15\right|\)

\(\left|x+\frac{4}{15}\right|-3,75=-2,15\)

\(\left|x+\frac{4}{15}\right|=1,6\)

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