Question

1.Tìm x

a.\(-\frac{2}{3}.|-\frac{1}{2}x-\frac{1}{3}|=0\)

Các bn ơi giúp mik với mai mik nộp rồi

 

 

Answer 1

\(-\frac{2}{3}.\left|-\frac{1}{2}x-\frac{1}{3}\right|=0\)

\(\Rightarrow\left|-\frac{1}{2}x-\frac{1}{3}\right|=0\)

\(\Rightarrow-\frac{1}{2}x-\frac{1}{3}=0\)

\(\Rightarrow-\frac{1}{2}x=\frac{1}{3}\)

\(\Rightarrow x=-\frac{2}{3}\)

Answer 2

\(\Leftrightarrow\left|-\frac{1}{2}x-\frac{1}{3}\right|=0\)

\(\Leftrightarrow\)\(\frac{-1}{2}x-\frac{1}{3}\)\(=0\)

\(\Leftrightarrow-\frac{1}{2}x=\frac{1}{3}\)

\(\Leftrightarrow x=\frac{-2}{3}\)

vậy....