Question

1,SO SANH :

\(A=\frac{2018}{2019}+\frac{2019}{2020}\)                                                   \(B=\frac{2018+2019}{2019+2020}\)

 

2,CHO :

\(S=\frac{5}{2^2}+\frac{5}{3^2}+\frac{5}{4^2}+...+\frac{5}{100^2}\) .CHỨNG TỎ RẰNG \(2< S< 5\)

3,SO SÁNH

\(A=\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}\)                                           \(B=\frac{2015+2016+201}{2016+2017+201}\)

 

.............................................GIÚP MK NHÉ CÁC BN..............................

 

Answer 1

\(B=\frac{2018+2019}{2019+2020}\)

\(\Rightarrow B=\frac{2018}{2019+2020}+\frac{2019}{2019+2020}\)

\(\Rightarrow B< \frac{2018}{2019}+\frac{2019}{2020}=A\)

Vậy B < A

Answer 2

\(B=\frac{2015+2016+2017}{2016+2017+2018}\)

\(\Rightarrow B=\frac{2015}{2016+2017+2018}+\frac{2016}{2016+2017+2018}+\frac{2017}{2016+2017+2018}\)

\(\Rightarrow B< \frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}=A\)

Vậy B < A

Answer 3

Câu hỏi của Nguyễn Bảo Trâm - Toán lớp 6 - Học toán với OnlineMath

Tham khảo câu 2

Answer 4

olm bi loi roi

Answer 5

ko bít

Answer 6

Bài 1:

Ta có:\(\frac{2018}{2019}>\frac{2018}{2019+2020}\)

\(\frac{2019}{2020}>\frac{2019}{2019+2020}\)

\(\Rightarrow\frac{2018}{2019}+\frac{2019}{2020}>\frac{2018}{2019+2020}\)\(+\frac{2019}{2019+2020}\)

\(\Rightarrow\frac{2018}{2019}+\frac{2019}{2020}>\frac{2018+2019}{2019+2020}\)

\(\Rightarrow A>B\)

Answer 7

CÂU 2 DỄ LẮM NHƯNG MIK KO BÍT VIẾT PS THÔNG CẢM NHA