Question

1.so sanh: \(a,A=2009^{2010}+2009^{2009}va\)\(B=2010^{2010}\)

2.so sanh cac so sau:

a,\(9^{21}\)va \(729^7\)

b,\(7^{14}\)va \(50^7\)

c,\(5^{30}\)va \(124^{10}\)

d,\(31^{11}\)va \(17^{14}\)

e,\(5^{36}\)va \(7^{24}\)

g,\(625^5\)va \(125^7\)

i,\(3^{2n}\)va \(2^{3n}\left(n\inℕ^∗\right)\)

m,\(5^{23}\)va \(6.5^{22}\)

f,\(7.2^{13}\)va \(2^{16}\)

h,\(21^{15}\)va \(27^5.49^8\)

k,\(199^{20}\)va \(2003^{15}\)

Answer 1

1.a=2009^2009(2009+1)

=2009^2009x2010. tự cm nốt

e tách số mũ ra nhé

a^m>a^n(m>n>0)