a) \(2^3=8\) ; \(3^2=9\)
=> \(2^3< 3^2\)
b) \(3^{210}\cdot3^{10}=3^{210+10}=3^{220}>3^{215}\)
=> \(3^{215}< 3^{210}.3^{10}\)
a,\(2^3\)và \(3^2\)
\(2^3=8\)\(3^2=9\)
Vì \(8< 9\Rightarrow2^3< 3^2\)
Vậy....
b,\(3^{215}\)và \(3^{210}.3^{10}\)
\(3^{215}\)và \(3^{220}\)
\(3^{215}< 3^{220}\Rightarrow3^{215}< 3^{210}.3^{10}\)
Vậy...
a) 23 = 8 ; 32 = 9
Vì 8 < 9 => 23 < 32
b) 3210.310 = 3210+10 = 3220 > 3215
=> 3215 < 3210.310
