a: \(=4x^2-2x-4x^2+4x-1-2x=-1\)
b: \(=4x^2-9-4x^2-8x-4=-8x-13\)
c: \(=\left(3x-2-3x-1\right)^2=\left(-3\right)^2=9\)
\(a,=4x^2-2x-4x^2+4x-1-2x=-1\\ b,=4x^2-9-4x^2-8x-4=-8x-13\\ c,=\left[\left(3x-2\right)-\left(3x+1\right)\right]^2=\left(3x-2-3x-1\right)^2=\left(-3\right)^2=9\)