\(1\frac{3}{8}-x=\frac{1}{3}\)
\(\frac{11}{8}-x=\frac{1}{3}\)
\(x=\frac{11}{8}-\frac{1}{3}\)
\(x=\frac{25}{24}\)
\(\frac{11}{8}\)-x=\(\frac{1}{3}\)
x=\(\frac{11}{8}\)-\(\frac{1}{3}\)
x=\(\frac{25}{24}\)
tk nhé
\(1\frac{3}{8}-x=\frac{1}{3}\)
\(\frac{11}{8}-x=\frac{1}{3}\)
\(x=\frac{11}{8}-\frac{1}{3}\)
\(x=\frac{25}{24}\)
\(\frac{11}{8}\)-x=\(\frac{1}{3}\)
x=\(\frac{11}{8}\)-\(\frac{1}{3}\)
x=\(\frac{25}{24}\)
tk nhé
Tập hợp các số nguyên x thỏa mãn \(\frac{1}{2}-\left(\frac{1}{3}+\frac{3}{4}\right)\) <x< \(\frac{8}{3}-\left(\frac{1}{5}+\frac{3}{4}\right)\)
Tìm x:
\(a,\left(3\frac{1}{4}:x\right)\cdot\left(-1\frac{1}{4}\right)=-\frac{5}{3}-\frac{5}{6}\\ b,\left(-1\frac{1}{5}+x\right):\left(-3\frac{3}{5}\right)=-\frac{7}{4}+\frac{1}{4}:\frac{1}{8}\)
\(\frac{2}{x-1.x-3}+\frac{5}{x-3.x-8}+\frac{12}{x-8.x-20}-\frac{1}{x-20}=\frac{-3}{4}\)
tìm x
Giúp mik vs thank
1.Tìm x:
a,\(1\frac{3}{4}.x+1\frac{1}{2}=-\frac{4}{5}\)
b,\(\frac{1}{4}+\frac{3}{4}.x=\frac{3}{4}\)
c,\(x.\left(\frac{1}{4}+\frac{1}{5}\right)-\left(\frac{1}{7}+\frac{1}{8}\right)=0\)
d,\(\frac{3}{35}-\left(\frac{3}{5}+x\right)=\frac{2}{7}\)
tim x
a)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)
b)\(2\frac{3}{4}x-1\frac{5}{8}x=1\)
c)\(\frac{3}{2}x-\frac{2}{5}=\frac{1}{3}x-\frac{1}{4}\)
d)\(2x-\frac{1}{4}=\frac{5}{6}-\frac{1}{2}x\)
e)\(\frac{-5}{6}+3x=\frac{2}{3}-\frac{1}{2}x\)
f)\(\frac{5}{2}x-\frac{3}{2}=x+\frac{29}{10}\)
g)\(\frac{2}{3}+\frac{7}{3}x=\frac{5}{4}x+\frac{1}{6}\)
h)\(\frac{1}{3}.x+\frac{2}{5}\left(x-1\right)=0\)
giup mk nha moi nguoi
a.\(\frac{x-6}{7}+\frac{x-7}{8}+\frac{x-8}{9}=\frac{x-9}{10}+\frac{x-10}{11}+_{\frac{x-11}{12}}\)
b.\(\frac{x-1}{2020}+\frac{x-2}{2019}-\frac{x-3}{2018}=\frac{x-4}{2017}\)
c.\(\left(\frac{3}{4}x+3\right)-\left(\frac{2}{3}x-4\right)-\left(\frac{1}{6}x+1\right)=\left(\frac{1}{3}x+4\right)-\left(\frac{1}{3}x-3\right)\)
giúp mk vs mk đg cần gấp
Thank you
\(\frac{20}{2+\frac{1}{3+\frac{1}{4+\frac{1}{x}}}}=\frac{2003}{2+\frac{3}{4+\frac{5}{6+\frac{7}{8}}}}\)
\(a,-\frac{4}{7}-x=\frac{3}{5}-2x\)
\(b,\frac{1}{2}-\left(\frac{1}{3}+\frac{3}{4}\right)\le x\le\frac{1}{24}-\left(\frac{1}{8}-\frac{1}{3}\right)\)
Tìm x:
\(\frac{2}{\left(x-1\right).\left(x-3\right)}+\frac{5}{\left(x-3\right).\left(x-8\right)}+\frac{12}{\left(x-8\right).\left(x-20\right)}-\frac{1}{x-20}=\frac{-3}{4}\)\(\frac{-3}{4}\)
Tìm x \(\frac{2}{\left(x-1\right)\times\left(x-3\right)}+\frac{5}{\left(x-3\right)\times\left(x-8\right)}+\frac{12}{\left(x-8\right)\times\left(x-20\right)}-\frac{1}{x-20}=-\frac{3}{4}\)-3/4