Các câu hỏi tương tự
\(SimplifyA=\frac{1+\frac{1}{3+}+\frac{1}{5}...+\frac{1}{99}}{\frac{1}{1x99}+\frac{1}{3x97}+...+\frac{1}{49x51}}\)
Simplify:\(A=\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{99}}{\frac{1}{1x99}+\frac{1}{3x97}+...+\frac{1}{49x51}}\)
tính
\(P=\frac{\frac{1}{1}+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1}.99+\frac{1}{3}.97+\frac{1}{5}.95+...+\frac{1}{97}.3+\frac{1}{99}.1}\)
Tích giá trị các biểu thức:
a) A = \(\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{97.3}+\frac{1}{99.1}}\)
b) B = \(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}{\frac{99}{1}+\frac{98}{2}+\frac{97}{3}+...+\frac{1}{99}}\)
\(H=\frac{\left(1+97\right)\left(1+\frac{97}{2}\right)\left(1+\frac{97}{3}\right)\left(1+\frac{97}{4}\right)+...+\left(1+\frac{97}{99}\right)}{\left(1+99\right)\left(1+\frac{99}{2}\right)\left(1+\frac{99}{3}\right)\left(1+\frac{99}{4}\right)+...+\left(1+\frac{99}{97}\right)}\)
\(\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{99}}{\frac{1}{1\times99}+\frac{1}{39\times7}+...+\frac{1}{97\times3}+\frac{1}{99\times1}}\)
\(TínhnhanhA=\frac{1+\frac{1}{3}+\frac{1}{5}+\frac{1}{7}+...+\frac{1}{97}+\frac{1}{99}}{1.\frac{1}{99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{95.5}+\frac{1}{97.3}+\frac{1}{99.1}}\)
A=\(\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+...+\frac{1}{97.3}+\frac{1}{99.1}}\)
Bài 1Tìm x biếtx-frac{37}{45}frac{4}{5.9}+frac{4}{9.13}+...+frac{4}{41.45}Bài 2 Tính giá trị các biểu thức sau a) A frac{1+frac{1}{3}+frac{1}{5}+...+frac{1}{97}+frac{1}{99}}{frac{1}{1.99}+frac{1}{3.97}+frac{1}{5.95}+...+frac{1}{97.3}+frac{1}{99.1}}b) B frac{frac{1}{2}+frac{1}{3}+frac{1}{4}+...+frac{1}{100}}{frac{99}{1}+frac{98}{2}+frac{97}{3}+...+frac{1}{99}}
Đọc tiếp
Bài 1Tìm x biết
\(x-\frac{37}{45}=\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{41.45}\)
Bài 2 Tính giá trị các biểu thức sau
a) A = \(\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{97.3}+\frac{1}{99.1}}\)
b) B = \(\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{100}}{\frac{99}{1}+\frac{98}{2}+\frac{97}{3}+...+\frac{1}{99}}\)