Các câu hỏi tương tự
Bài 1: Thực hiện phép tính:
A= (1+\(\frac{1}{1.3}\)).( 1+ \(\frac{1}{2.4}\)).( 1+\(\frac{1}{3.5}\))....(\(1+\frac{1}{2017.2019}\))
S=\(\frac{1}{1.3}+\frac{1}{2.4}+\frac{1}{3.5}+...+\frac{1}{7.9}+\frac{1}{8.10}\)
bai 1: s=\(\frac{1}{1.2}+\frac{1}{3.4}+...+\frac{1}{199.200}\)
bai 2: s=\(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}\text{+}...\text{+}\frac{1}{2017.2019}\)
Chứng minh rằng: \(\frac{1}{1.3}+\frac{1}{2.4}+\frac{1}{3.5}+\frac{1}{4.6}+...+\frac{1}{97.99}+\frac{1}{98.100}< \frac{3}{4}\)
\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{2014.2016}\right)\)
Tính Q=\(\frac{1.3}{3.5}+\frac{2.4}{5.7}+\frac{3.5}{7.9}+.....+\frac{\left(n-1\right)\left(n+1\right)}{\left(2n-1\right)\left(2n+1\right)}+......+\frac{1002.1004}{2005.2007}\)
Thực hiện phép tinh sau:
\(\frac{1}{1.3}+\frac{1}{2.4}+\frac{1}{3.5}+\frac{1}{4.6}+\frac{1}{5.7}+\frac{1}{6.8}+\frac{1}{7.9}+\frac{1}{8.10}\)
Tính A=\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right).....\left(1+\frac{1}{99.101}\right)\)
A\(A=\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)........\left(1+\frac{1}{2014.2016}\right)\)