Các câu hỏi tương tự
1.CMR:
\(\frac{1}{101}+\frac{1}{102}+..+\frac{1}{199}+\frac{1}{200}< 1\)
\(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{32}>3\)
1.CMR:
\(\frac{1}{101}+\frac{1}{102}+..+\frac{1}{199}+\frac{1}{200}< 1\)
\(1+\frac{1}{2}+\frac{1}{3}+..+\frac{1}{32}>3\)
Chứng minh :
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
Chứng tỏ :
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
CM \(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\frac{1}{5}-\frac{1}{6}+....+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+....+\frac{1}{200}\)
\(CTR:1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+.....+\frac{1}{200}\)
CMR:
a, \(100-\left(1+\frac{1}{2}+\frac{1}{3}+..+\frac{1}{100}\right)=\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+..+\frac{99}{100}\)
b, \(\left(1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{199}\right)-\left(\frac{1}{2}+\frac{1}{4}+..+\frac{1}{200}\right)=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
Giải nhanh giùm mình nhé!!!!!!!!!!!!!!
Chứng minh rằng :
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
11 tháng 3 2018 lúc 11:00
\(\text{Chứng tỏ:}\)
\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{199}-\frac{1}{200}=\frac{1}{101}+\frac{1}{102}+.....+\frac{1}{200}\)