A< 1+1/(23-2)+1/(33-3)+...+1/(n3-n)
Đặt B=1/(23-2)..... =>B=1/1.2.3+1/2.3.4+...+1/(n-1)n(n+1) =1/2.(1/1.2-1/2.3+1/2.3-1/3.4+1/3.4....-1/n(n+1))
=1/2.(1/2-1/n(n+1))=1/4-1/2.n.(n+1)<1/4
=>B<1/4 =>A=B+1<(1/4)+1
=>A<5/4
999 - 888 - 111 + 111 - 111 + 111 - 111
= 111 - 111 + 111 -111 + 111 - 111
= 0 + 111 - 111 + 111 - 111
= 111 - 111 + 111 - 111
= 0 + 111 - 111
= 111 - 111
= 0
Đáp số: 0