\(\frac{n+1}{n-2}=\frac{\left(n-2\right)+3}{n-2}=\frac{n-2}{n-2}+\frac{3}{n-2}=1+\frac{3}{n-2}\)
Để \(\frac{3}{n-2}\in Z\) <=> 3 ⋮ n - 2 => n - 2 ∈ Ư ( 3 ) = { - 3 ; - 1 ; 1 ; 3 }
=> n ∈ { - 1 ; 1 ; 3 ; 5 }
\(\frac{n+1}{n-2}=\frac{\left(n-2\right)+3}{n-2}=\frac{n-2}{n-2}+\frac{3}{n-2}=1+\frac{3}{n-2}\)
Để \(\frac{3}{n-2}\in Z\) <=> 3 ⋮ n - 2 => n - 2 ∈ Ư ( 3 ) = { - 3 ; - 1 ; 1 ; 3 }
=> n ∈ { - 1 ; 1 ; 3 ; 5 }
cho phan so A= (6n- 1)/3n+2
tim n thuocZ de a co gia tri nguyen
tim n thuoc Z de a co gia tri lon nhat
Cho A=n+1/n-2
a)Tim n thuoc Z de A co gia tri nguyen.
b)Tim n thuoc de A co gia tri nguyen lon nhat.
cho A=6n-1/3n+1(n thuoc z) hoi a tim n de A nguyen b tim n de A co gia tri nho nhat
cho bieu thuc 2n+1/n+5(n thuoc Z)
a, tim n de Pco gia tri la 1 so nguyen
b,tim gia tri lon nhat,gia tri nho nhat cua P
Cho B=9n-1/3n+2
a) tim n thuoc Z de B nhan gia tri nguyen
b)tim n thuoc z de B nhan gia tri lon nhat
Giup mk nhanh nhanh nha
tim n thuoc z de phan so sau a=4n-1/2n+3 co gia tri nguyen
cho phan so A=n+1/n-3 (n thuoc z;n khac 3)
tim n de A co gia tri nguyen
Cho cac bieu thuc
A=n+6 phan n-5 va B=3n-9 phan n-6
a/ Tim gia tri nguyen cua n de A, B la phan so ?
b/ Tim gia tri nguyen cua n de A, B co gia tri nguyen?
c/ Tim gia tri nguyen cua n de A, B co gia tri nguyen lon nhat?
cho phan so \(B=\frac{4n+1}{2n-3}\)n thuoc z
a, tim n de phan so B toi gian
b, tim n de B dat gia tri nho nhat , gia tri lon nhat va tinh cac gia tri do.