1bac : 3 = abc
1000 + abc = abc x 3
1000 = abc x 3 - abc x 1
1000 = abc x (3 - 1)
1000 = abc x 2
abc = 1000 : 2
abc = 500
1abc = 1000 + abc
Ta co:
1000 + abc = 3abc
1000 = 3abc - abc
1000 = 2abc
abc = 1000:2=500
Vay abc = 500
Dáp so: 500
Ta có:
1000 + abc = 3abc
1000 = 3abc - abc
1000 = 2abc
Vậy abc = 1000 : 2 = 500
1abc : 3 = abc
1000 + abc = abc * 3
1000 = abc * 3 - abc * 1
1000 = abc * ( 3 - 1 )
1000 = abc * 2
abc = 1000 : 2
abc = 500