1999.10001.1998-1998.10001.1999
=1999.1998(10001-10001)
=1998.1999.0=0
________________________
li-ke cho mk nhé bn
1999.10001.1998-1998.10001.1999
=1999.1998(10001-10001)
=1998.1999.0 = 0
1999.10001.1998-1998.10001.1999
=1999.1998(10001-10001)
=1998.1999.0=0
________________________
li-ke cho mk nhé bn
1999.10001.1998-1998.10001.1999
=1999.1998(10001-10001)
=1998.1999.0 = 0
a ( 1+2+3+....+100) * (1^2+ 2^2 + 3^3+....+100^2) * ( 65. 111- 13. 15. 37)
b 1999. 1999. 1998- 1998. 1998. 1999
Cho A=79/1999+191/1998+947/1997+673/1998+110/1999
so sánh:A=1999^1999+1/1999^1998+1
B=1999^2000+1/1999^1999+1
19991999×1998-1998×1999
19991999×1998-1998×1999
Cho A=\(\frac{79}{1999}+\frac{191}{1998}+\frac{947}{1997}+\frac{673}{1998}+\frac{110}{1999}\)
Chứng minh: (1999 + 1999^2 + 1999^3 +...+ 1999^1998) chia hết cho 2000
CMR:
1) 19971999 - 19971998 chia hết cho 4
2) 19971998 - 19981999 chia hết cho 4
tìm số dư trong phép chia
(19971998+19981999+19992000) chia cho 111