Answer:
\(\left(1+\frac{8}{10}\right).\left(1+\frac{8}{22}\right).\left(1+\frac{8}{36}\right)...\left(1+\frac{8}{8352}\right)\)
\(=\frac{18}{10}.\frac{30}{22}.\frac{44}{36}...\frac{8360}{8352}\)
\(=\frac{2.9.3.10.4.11....88.95}{1.10.2.11.3.12...87.96}\)
\(=\frac{\left(2.3.4...8\right).\left(9.10.11...95\right)}{\left(1.2.3...87\right).\left(10.11...96\right)}\)
\(=\frac{9.88}{96}\)
\(=\frac{3}{4}\)