\(16:\left(\frac{3}{5}x+\frac{8}{21}+9\right)=\frac{7}{10}\)
\(\frac{3}{5}x+\frac{8}{21}+9=\frac{160}{7}\)
\(\frac{3}{5}x=\frac{283}{21}\)
\(x=\frac{1415}{63}\)
Vậy ...
\(16:\left[\frac{3}{5}\times x+\frac{8}{21}+9\right]=\frac{7}{10}\)
\(\Rightarrow\left[\frac{3}{5}\times x+\frac{8}{21}+9\right]=16:\frac{7}{10}\)
\(\Rightarrow\left[\frac{3}{5}\times x+\frac{8}{21}+9\right]=16\times\frac{10}{7}\)
\(\Rightarrow\frac{3}{5}\times x+\frac{8}{21}+9=\frac{160}{7}\)
\(\Rightarrow\frac{3}{5}\times x=\frac{160}{7}-9-\frac{8}{21}\)
\(\Rightarrow\frac{3}{5}\times x=\frac{283}{21}\)
\(\Rightarrow x=\frac{283}{21}:\frac{3}{5}=\frac{283}{21}\cdot\frac{5}{3}=\frac{1415}{63}=22\frac{29}{63}\)