\(\frac{15}{x-9}=\frac{20}{y-12}=\frac{40}{z-24}\) và \(x.y=1200\) (Sửa đề)
Ta có:
\(\frac{x-9}{15}=\frac{y-12}{20}=\frac{z-24}{40}\Rightarrow\frac{x}{15}.\frac{9}{15}=\frac{y}{20}.\frac{12}{20}=\frac{z}{40}.\frac{24}{40}\)
Mà \(\frac{9}{15}=\frac{12}{20}=\frac{24}{40}=\frac{3}{5}\Rightarrow\frac{x}{15}=\frac{y}{20}=\frac{z}{40}\)
\(\Rightarrow\frac{x^2}{15^2}=\frac{y^2}{20^2}=\frac{z^2}{40^2}=\frac{x.y}{15.20}=\frac{1200}{300}=2^2\)
\(\Rightarrow x^2=2^2.15=\left(2.15\right)^2=30^2\Rightarrow x=\pm30\)
\(\Rightarrow y^2=2^2.20^2=\left(2.20\right)^2=40^2\Rightarrow y=\pm40\)
\(\Rightarrow z^2=2^2.40^2=\left(2.40\right)^2=80^2\Rightarrow z=\pm80\)
