\(\left(\frac{1}{4}x-1\right)+\left(\frac{5}{6}x-2\right)-\left(\frac{3}{8}x+1\right)=4.5\)
\(\frac{1}{4}x-1+\frac{5}{6}x-2-\frac{3}{8}x-1=4.5\)
\(\left(\frac{1}{4}x+\frac{5}{6}x-\frac{3}{8}x\right)-\left(1+1+2\right)=4.5\)
\(\frac{17}{24}x-4=4.5\)
\(\frac{17}{24}x=4.5+4\)
\(\frac{17}{24}x=9.5\)
\(x=9.5\div\frac{17}{24}\)
\(x=\frac{228}{17}\)
[1/4x-1]+[5/6x-2]-[3/8x+5]-3,5
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
a,Tìm x biết:(1/4x-1)+(5/6x-2)-(3/8x+5)=3,5
b, Tìm nghiệm các của đa thức: x2+1/2x và (3x+5)x(5x-2x)
P(x)=4x^3+5x^2-4x^3+6x+8x-2
Q(x)=1/7x^3-2/5x^2-1/7x^3+2/5x^2-2020
x mũ 2-x=0
x mũ 2 +2x=0
x mũ 2-3x=0
3x mũ 2 +4=0
[1/4x-1]+[5/6x-2]-[3/8x+5]-3,5=0
Bài 1: Tìm nghiệm của các đa thức sau:
1, (x-4)2-(2x+1)2
2, x3 +x2-4x-4
3, x3+x2+4
4, 2x3 +5x2+5x+2
5, 6x4-5x3-38x2-5x+6
6, (8x+5)(4x+3)(2x+1)-9
7, (x-6)(x4)(x+1)(x-1)
8, (x+5)+(x+7)4-12
9, 3x4-7x2-10
10, (8x-7)(8x-5)(2x-1)(4x-1)-9
Thực hiện phép chia:
a) \((3x^5-9x^6+12x^9):3x\)
b) \((6x^4+4x^3+8x^2):(2x)\)
c) \((8x^6+16x^5-10x^4):(2x^4)\)
d) \((4x^4+6x^5+14x^7):(2x^3)\)
cho da thuc f(x) =-6x^3 + 8x^2 -1/2 -4^4 va g(x) = 4x^4+5/2-5x^2+6x^3
tinh h(x)=f(x)+g(x)
chung to h(x) khong co nghiem
\(X^2-1\)
\(X^2+6X+9\)
\(4X^2-9\)
\(16X^2-8X+1\)
