Ta có:
\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\frac{15}{60}+\frac{1}{3}:\left(2x-1\right)=-\frac{300}{60}\)
\(\Rightarrow\frac{20}{60}:\left(2x-1\right)=-\frac{300}{60}-\frac{15}{60}=-\frac{315}{60}\)
\(2x-1=-\frac{315}{60}.\frac{1}{3}=-\frac{315}{180}=-\frac{7}{4}\)
\(2x=-\frac{7}{4}+1=-\frac{7}{4}+\frac{4}{4}=-\frac{3}{4}\)
\(\Rightarrow x=\frac{-3}{4}:2=-\frac{3}{8}\)
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