\(\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
\(=\frac{\left(3^{14}-1\right):\left(3^4-1\right)}{\left(3^{14}-1\right):\left(3^2-1\right)}\)
\(=\frac{3^2-1}{3^4-1}=\frac{9-1}{81-1}=\frac{8}{10}=\frac{1}{10}\)
Tính
1. 6/5 - 1/4 + 4/5 - 3/4
2. 7/9 - 5/12 + 2/9 - 7/12
3. -4/15 + 5/13 - 11/15 + 8/13
4. 9/15 - 7/13 +6/15 - 6/13
5. 12/5 - 3/7 + 3/5 - 4/7
6. 6/5 - 1/4 + 4/5 - 3/4 + 1/2
7. 13/7 - 8/6 + 8/7 - 4/6 - 1/3
6/5 có nghĩa là sáu phần năm đó nha mn
\(\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
mọi người ơi giúp mình nha rồi muốn gì mình cũng đồng ý nhưng phải trong phạm vi cho phép
giúp mình nha mình đang cần rất gấp
giúp nha
Rút gọn
1+3^4+3^8+3^12/1+3^2+3^4+3^6+3^8+3^10+3^12+3^14
Tính:
a) -5/7(14/5 - 7/10) : |-2/3| - 3/4(8/9 + 16/3) + 10/3(1/3 + 1/5)
b) 17/-26(1/6 - 5/3) : 17/13 - 20/3(2/5 - 1/4) + 2/3(6/5 - 9/2)
c) -8/9(9/8 - 3/2) + 5/4 : (5/2 - 15/4) - 3/4(10/9 - 8/3) : (-1/3)
d) 21/10 : (12/5 - 9/10) . (-4/7) - 3/2(1/6 - 7/12) + 1/5(3/2 - 1/4)
Rút gọn
;
A=1+3^4+3^8+3^12/1+3^2+3^4+3^6+3^8+3^10+3^12
\(B=\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
1, 1/6 (2x - 3) = -1/2 (x-1/4) - 2/3
2, 17/-8 : 3/4 + 2 . | 3/2x - 1 | = -1/2
3, | x^2 + 1/2 | - 15 1/2 = -12 3/4
Lam giup mik nha (nhanh)
Rút gọn: \(A=\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
rút gọn
Q=\(\frac{1+3^4+3^8+3^{12}}{1+3^2+3^4+3^6+3^8+3^{10}+3^{12}+3^{14}}\)
