Ta có \(\left(-\frac{1}{3}+2x\right)^3=\frac{-1}{125}\)
\(\Rightarrow\left(-\frac{1}{3}+2x\right)^3=-\left(\frac{1}{5}\right)^3\)
\(\Rightarrow2x=-\frac{1}{5}+\frac{1}{3}\)
\(\Rightarrow2x=\frac{2}{15}\)
\(\Rightarrow x=\frac{1}{15}\)
\(\Rightarrow2x=-\frac{1}{5}+\frac{1}{3}\)
1:Tìm x, biết:
a) (3/5)^2x-1 = 125/27
b)1/2+(1/2.3)+(1/3.4)+...+(1/2015.2016)-2x=1/2-1/2016
c)/2x^2+/x-2//=2x^2+3
Tìm x, biết:
a, (3/5)^2x-1=125/27
b,1/2+1/2.3+1/3.4+...+1/2015.2016 - 2x=1/2-1/2016
c,/2x^2+/x-2//=2x^2+3
A) (x+2/3)3=1/8
B) 52x-1-125=0
C) 81/32x+1=3
Em cần gấp chiều nộp rồi ạ
1 a)
|2x+1|-3=4x
b) |-3x+4|-5=2x+1
2
a) 5x=125
b) 32x=81
c) 52x-3-2 . 5 =52 .3
tìm x biết
a) /2x-50\+/5x-125\-/3x+75/=100
b) 2x+/x-3\=6
c) 3x-1= /2x-1/
(1/125-1/1^3).(1/125-1/2^3).(1/125-1/3^3)...(1/125-1/25^3)
(1/125 - 1/ 1^3).(1/125 - 1/ 2^3).(1/125 - 1/ 3^3)....(1/125 - 1/ 25^3).
\(\left(2x+1\right)^3=\frac{125}{27}\)
Tính: (1/125-1/2^3).(1/125-1/3^3).(1/125-1/4^3).............(1/125-1/100^3)
