Đặt 1.3+2.5+3.7+...+20.41 = A ta có :
A = 1.3+2.5+3.7+.......+20.41
A = 1.(2+1) + 2. (3+2) +3.(4+3) +...+ 20.(20+21)
A = 1.2+12 + 2.3+22 + 3.4+32 + ...+ 20.21+202
A = (1.2+ 2.3 + 3.4 + ...+ 20.21) + (12 + 22 +32 +...+ 202)
Đặt 1.2+ 2.3 + 3.4 + ...+ 20.21 = B ta có:
B = 1.2+ 2.3 + 3.4 + ...+ 20.21
3B = (1.2+ 2.3 + 3.4 + ...+ 20.21)3
3B = 1.2.3+ 2.3.3 + 3.4.3 + ...+ 20.21.3
3B = 1.2.3 + 2.3.(4-1) + 3.4.(5-2) + ... + 20.21.(22-19)
3B = 1.2.3 + 2.3.4 -1.2.3 + 3.4.5 - 2.3.4 +...+ 20.21.22 - 19.20.21
3B = 20.21.22
B = 9240 : 3
B = 3080
Đặt (12 + 22 +32 +...+ 202) = C ta có :
C = 12 + 22 +32 +...+ 202
C = 1.1 + 2.2 + 3.3 + ... + 20.20
C = 1.(2-1) + 2.(3-1) + 3.(4-1) + ... + 20.(21-1)
C = 1.2-1+ 2.3-2 + 3.4-3 + ...+ 20.21-20
C = (1.2+ 2.3 + 3.4 + ...+ 20.21) - (1+2+3+...+20)
Mà 1.2+ 2.3 + 3.4 + ...+ 20.21 = B = 3080
=> C = 3080 - (1+2+3+...+20)
C = 3080 - [(20+1) . 20 :2]
C = 3080 -210
C = 2870
Mà A = B + C => A = 3080 + 2870 => A = 5950