\(\frac{1}{3}\) + \(\frac{1}{6}\) + \(\frac{1}{10}\) + ... + \(\frac{1}{x\left(x+1\right):2}\)
= \(\left(1-\frac{1}{2018}\right)-\frac{1}{2018}\)
= \(\frac{2017}{2018}-\frac{1}{2018}\)
= \(\frac{2016}{2018}=\frac{1008}{1009}\)
1/3 +1/6+ 1/10 + .......+2/x(x+1 ) = 2016/2018
giúp tôi với
tìm số tự nhiên x,biết:1/3+1/6+...+1/x*(x+1)/2=2016/2018
Tìm x biết
a) \(\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2019}\right).x=\frac{2018}{1}+\frac{2017}{2}+\frac{2016}{3}+...+\frac{2}{2017}+\frac{1}{2018}\)
b) \(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{2017}{2019}\)
Bài 1:
a, C = 1 + 5^2 + 5^4 + 5^6 +...+ 5^2018
b, D = 2 x 4 + 4 x 6 + 6 x 8 + 8 x 10 + ... + 2016 x 2018
Tìm số tự nhiên x,biết:\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{x\cdot\left(x+1\right):2}=\frac{2016}{2018}\)
Ai làm được?Giúp mình đi,mai nộp rồi
A=1+4^2+4^4+4^6+....+4^2016+4^2018.Tìmx biết 15*x=2^3*x-1
1+1/3+1/6+1/10+.......+1/x(x+1):2=2018/2019
2/5×(x-1)+1=3/5
(2/7×x+1)×(3-1/2×x)=0
5/4×x+1=1/2x+3/4
X-2020/10^2+x-202^0/10^3+x-2020/10^4=0
0x+1/2018+x+2/2017=x+3/2016-x+4/2015
2015
Nhanh tk nha
5^x+2.5^x+4=10.......0:2^2018
2018 so 0
Tim so co 5 c/s khac nhau abcde ma abcd=5c+1^2
so sanh 2016/1027+2017/2018+2018/2016va 1/3+1/4+........+1/23
giải chi tiết nhé tick cho
