Các câu hỏi tương tự
Tìm x biếta,left(frac{4}{5}right)^{2x+7}text{}frac{625}{256}b,frac{7^{x+2}+7^{x+1}+7^x}{57}text{}frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}c,left(4x-3right)^4text{}left(4x-3right)^2d,frac{2x+3}{5x+2}text{}frac{4x+5}{10x+2}e,frac{3x-1}{40-5x}text{}frac{2x-3x}{5x-34}f,frac{15}{x-9}text{}frac{20}{y-12}text{}frac{40}{z-2x} và xytext{}1200
Đọc tiếp
Tìm x biết
a,\(\left(\frac{4}{5}\right)^{2x+7}\text{=}\frac{625}{256}\)
b,\(\frac{7^{x+2}+7^{x+1}+7^x}{57}\text{=}\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
c,\(\left(4x-3\right)^4\text{=}\left(4x-3\right)^2\)
d,\(\frac{2x+3}{5x+2}\text{=}\frac{4x+5}{10x+2}\)
e,\(\frac{3x-1}{40-5x}\text{=}\frac{2x-3x}{5x-34}\)
f,\(\frac{15}{x-9}\text{=}\frac{20}{y-12}\text{=}\frac{40}{z-2x}\) và \(xy\text{=}1200\)
tìm x
1 , \(\left|\frac{3}{2}x-1\right|-2x=1\)
2, | 7 - 2x | + 7 = 2x
3 , | 5x - 2 | +2 = 5x
4 , \(\left|x\left(x^2-\frac{5}{4}\right)\right|=x\)
a) \(\left(\frac{4}{5}\right)^5:x=\left(\frac{4}{7}\right)^7\)
b) \(3^x +3^{x+1}=108\)
c) \(2^{6+5x}=16^9\)
d) \(\left|2x+\frac{1}{3}\right|=\frac{2}{5}\)
e) \(\left|2x-\frac{1}{4}\right|-\frac{3}{4}=\frac{1}{2}\)
Tìm x biết :
a, 4.(18 - 5x) - 12.(3x - 7) = 15.(2x - 16) - 6(x + 14)
b, 5.(3x + 5) - 4.(2x - 3) = 5x + 3.(2x + 12) + 1
c, 2.(5x - 8) - 3.(4x - 5) = 4.(3x - 4) + 11
d, (3x + 2)(2x + 9) - (x + 2)(6x + 1) = (x + 1) - (x - 6)
e, (8x - 3)(3x + 2) - (4x + 7)(x + 4)= (2x + 1)(5x - 1) - 33
K= \(\frac{2x-9}{x^2-5x+6}-\frac{x+3}{x-2}-\frac{2x+1}{3-x}\)
Tím x để K<1
1/2x + 2/9 =7/6
2/5x -1/3 = 2/3
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )30 b) 2x(3-2x) + 2x(2x-1)15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)1 d) (x+2) (x+2)- (x -3)(x+1) 9
e) (4x+1)(6x-3) 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) 14
Đọc tiếp
: Tìm x, biết:
a) 3x( 4x- 1) - 2x(6x- 3 )=30 b) 2x(3-2x) + 2x(2x-1)=15
c) (5x-2)(4x-1) + (10x +3)(2x - 1)=1 d) (x+2) (x+2)- (x -3)(x+1) = 9
e) (4x+1)(6x-3) = 7 + (3x – 2)(8x + 9) g) (10x+2)(4x- 1)- (8x -3)(5x+2) =14
Bài 1: Tìm nghiệm của các đa thức sau:
1, (x-4)2-(2x+1)2
2, x3 +x2-4x-4
3, x3+x2+4
4, 2x3 +5x2+5x+2
5, 6x4-5x3-38x2-5x+6
6, (8x+5)(4x+3)(2x+1)-9
7, (x-6)(x4)(x+1)(x-1)
8, (x+5)+(x+7)4-12
9, 3x4-7x2-10
10, (8x-7)(8x-5)(2x-1)(4x-1)-9
a) \(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
b)\(\frac{x+1}{2x+1}=\frac{0.5x+2}{x+3}\)