1+2+22 +23+ ...+299+2100
2A=2+22+23+...+2101
2A-a =[2+2mu2+2mu3+...+2mu 101] -[1+2+2mu 2+2 mu 3+...+2 mu 100]
1A=A=2 mu 101 - 2=the nao ban tu nghi nhe nho **** cho minh nha
1+2+22 +23+ ...+299+2100
2A=2+22+23+...+2101
2A-a =[2+2mu2+2mu3+...+2mu 101] -[1+2+2mu 2+2 mu 3+...+2 mu 100]
1A=A=2 mu 101 - 2=the nao ban tu nghi nhe nho **** cho minh nha
1.Tính
B=1/2+2/2^2+3/2^3+4/2^4+.....+99/2^99+100/2^100
Tính tổng:
a) A= 1^2*2 + 2^2 *3 + 3^2*4 +...+ 99^2*100
b) B= 1*2^2 + 2*3^2 + 3*4^2 +...+ 99*100^2
c) C= 1^3 + 2^3 + 3^3 +...+ 99^3
Tính A=1+3/2^3+4/2^4+......+99/2^99+100/2^100
c/m
a/
1/2!+2/3!+3/4!+...+99/100!<1
b/
1*2-1/2!+2*3-1/3!+3*4-1/4!+...+99*100-1/100!<2
1/ Cho A= \(\dfrac{1}{3}\)-\(\dfrac{2}{3^2}\)+\(\dfrac{3}{3^3}\)-\(\dfrac{4}{3^4}\)+.....+\(\dfrac{99}{3^{99}}\)-\(\dfrac{100}{3^{100}}\) Chứng minh A < \(\dfrac{3}{16}\)
2/ Cho B=(\(\dfrac{1}{2^2}\)-1)(\(\dfrac{1}{3^2}\)-1)....(\(\dfrac{1}{100^2}\)-1) So sánh B và \(\dfrac{-1}{2}\)
Tính tổng:
\(A=1+3+3^2+3^3+...+3^{99}+3^{100}\)100
\(B=1-2+2^2-2^3+2^4-...-2^{99}+2^{100}\)
tính nhanh (1+2+3+...+99+100).(1/2-1/3-1/7-1/9)(63.1,2-21.3,6)/1-2+3-4+...+99-100
A=(1+2+3+...+99+100)(1/2-1/3-1/7-1/9)(63.1,2-21.3,6)/1-2+3-4+...+99-100
a)A=1-2+3-4+...+99-100
b)B=1-2-3+4+5-6-7+...+97-98-99+100
c)C=2100-299s-998-...-22-2-1
giup mik vs a
1/1*2 - 1/2*3 - 1/3*4- ..... -1/98*99=1/100+1/99*100