\(\frac{49}{5360}\)+\(\frac{1}{272}\)+\(\frac{1}{306}\)=\(\frac{73}{5695}\)+\(\frac{1}{306}\)=\(\frac{97}{6030}\)
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\(\frac{49}{5360}\)+\(\frac{1}{272}\)+\(\frac{1}{306}\)=\(\frac{73}{5695}\)+\(\frac{1}{306}\)=\(\frac{97}{6030}\)
Tính hợp lý nhất
a, 1/210+1/240+1/272+1/306
b, 191/210+161/240+129/272+95/306
giúp mình với huhuhu
1/210+1/240+1/272+1/306
1/210+1/240+1/272+1/306
\( {1 \over 210}+{1 \over 240}+{1 \over 272}+{1 \over 306}\)
1 phần 210 + 1phần 240 + 1 phần 272 + 1 phần 306
191/210+161/240+129/272+95/306
191/210+161/240+129/272+96/306
191/210+161/240+129/272+96/306
Tinh : B = 191/210 + 161/240 + 129/272 + 95/306