\(120-4\left(1-x\right)=106-3x\)
\(120-4+4x+3x=106\)
\(116+7x=106\)
\(7x=-10\)
\(x=\frac{-10}{7}\)
120 - 4(1-x) = 106 - 3x
120 - 4 - x = 106 - 3x
116 - x = 106 - 3x
x - 3x = 116 - 106
-2x = 10
x = 10 : ( -2 )
x = -5
\(120-4\left(1-x\right)=106\)
\(120-4+4x+3x=106\)
\(116+7x=106\)
\(7x=-10\)
\(\Rightarrow x=\frac{-10}{7}\)
120 - 4(1-x) = 106 - 3x
120 - 4 + 4x + 3x = 106
116 + 7x = 106
7x = 106 - 116
7x = -10
x = ( -10 ) : 7
x = \(\frac{-10}{7}\)
120 - 4 ( 1 - x ) = 106 - 3x
120 - 4 + 4x = 106 - 3x
4x + 3x = -120 + 4 + 106
7x = -10
x = -10 : 7
x = \(\frac{-10}{7}\)
\(120-4\left(1-x\right)=106-3x\)
Chuyển vế x sang 1 bên , vế số sang một bên , ta có :
\(120-106=4\left(1-x\right)-3x\)
= \(14=4-4x-3x\)
=\(14-4=-4x-3x\)
=\(10=-7x\)
=\(\frac{-10}{7}=x\)
