\(=\frac{120-0,5\cdot40\cdot5\cdot0,2\cdot20\cdot0,25-20}{1+5+9+.....+33+37}\)
\(=\frac{120-20-\left(0,5\cdot20\right)\cdot\left(5\cdot0,2\right)\cdot\left(40\cdot0,25\right)}{1+5+9+.....+33+37}\)
\(=\frac{100-10\cdot1\cdot10}{1+5+9+.....+33+37}\)
\(=\frac{100-100}{1+5+9+.....+33+37}\)
\(=\frac{0}{1+5+9+.....+33+37}\)
\(=0\)
Ta có:\(120-0,5\times40\times5\times0,2\times20\times0,25-20=120-100-20=0\)
\(\Rightarrow\frac{120-0,5\times40\times5\times0,2\times20\times0,25}{1+5+.......+37}=\frac{0}{1+5+9+.....+37}=0\)
Vậy...........