\(\dfrac{1}{2}\times x+\dfrac{3}{5}\times\left(x-2\right)=3\)
\(\dfrac{1}{2}x+\dfrac{3}{5}x-\dfrac{3}{5}\times2=3\)
\(x\times\left(\dfrac{1}{2}+\dfrac{3}{5}\right)-\dfrac{6}{5}=3\)
\(x\times\dfrac{11}{10}-\dfrac{6}{5}=3\)
\(x\times\dfrac{11}{10}=3+\dfrac{6}{5}=\dfrac{21}{5}\)
\(x=\dfrac{21}{5}\div\dfrac{11}{10}=\dfrac{21}{5}\times\dfrac{11}{10}\)
\(x=\dfrac{42}{11}\)
Vậy \(x=\dfrac{42}{11}\)