\(\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)
\(\left(\frac{1}{2}\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)
\(\Rightarrow2.x-1=3\)
\(2.x=3+1\)
\(2.x=4\)
\(x=4:2\)
\(x=2\)
Vậy \(x=2\)
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\(\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)
\(\left(\frac{1}{2}\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)
\(\Rightarrow\text{ }2x-1=3\)
\(2x=3+1\)
\(2x=4\)
\(x=4\text{ : }2\)
\(x=2\)
\(\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)
\(\left(\frac{1}{2}\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)
\(\Rightarrow\text{ }2x-1=3\)
\(2x=3+1\)
\(2x=4\)
\(x=4\text{ : }2\)
\(x=2\)
\(\left(\frac{1}{2}\right)^{2x-1}=\frac{1}{8}\)
<=> \(\left(\frac{1}{2}\right)^{2x-1}=\left(\frac{1}{2}\right)^3\)
<=> 2x - 1 = 3
<=> x = 2
(1/2)2x-1=1/8
(1/2)2x-1=(1/2)3
2x-1=3
2x=3+1
2x=4
x=4:2
x=2
vậy x=2