Question

1/2 . 2^n + 2^2+n = 9. 2^5

( Một phần hai nhân hai mũ n cọng hai mũ hai cọng n = Chín nhân hai mũ năm .😢😢😢🙏🙏)

Answer 1

\(\frac{1}{2}.2^n+2^{2+n}=9.2^5\)

\(\frac{1}{2}.2^n+4.2^n=9.2^5\)

\(2^n.\left(\frac{1}{2}+4\right)=9.2^5\)

\(2^n.\frac{9}{2}=9.2^5\)

\(2^n=9.\frac{2}{9}.2^5\)

\(2^n=2.2^5\)

\(2^n=2^6\)

\(\Rightarrow n=6\)

Answer 2

\(\frac{1}{2}\)\(\times\)\(2^n\)\(+\)\(2^{2+n}\)\(=\)\(9\)\(\times\)\(2^5\)

\(\frac{1}{2}\)\(\times\)\(2^n\)\(\times\)\((\)\(1\)\(+\)\(2^2\)\()\)\(=\)\(9\)\(\times\)\(2^5\)

\(\frac{1}{2}\)\(\times\)\(2^n\)\(\times\)\(5\)\(=\)\(9\)\(\times\)\(2^5\)

\(2^n\)\(=\)\(9\)\(\times\)\(32\)\(\div\)\(5\)\(\times\)\(2\)

\(2^n\)\(=\)115,2