\(11.\left(x-6\right)=\left(4.x\right)+11\)
\(11x-66=4x+11\)
\(11x-4x=11+66\)
\(7x=77\)
\(x=11\)
11.(x-6) = (4.x)+11
11.x - 66 = 4x + 11
=> 11.x - 4x = 11 + 66
7x = 77
x = 11
11. (x-6) = (4.x )+11
11.x - 66 = 4x + 11
=> 11.x - 4x = 11 + 66
7x=77
x=11
\(11\left(x-6\right)=4x+11\)
\(\Leftrightarrow11x-66=4x+11\)
\(\Leftrightarrow11x-4x=11+66\)
\(\Leftrightarrow7x=77\)
\(\Leftrightarrow x=77:7\)
\(\Leftrightarrow x=11\)
Vậy x=11